Calculate the reaction enthalpy for the formation of anhydrous aluminum bromide, 2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s), from the following data:

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2 Al(s) + 6 HBr(aq) - HBr(g) H₂(g) + Br₂ (1) AlBr3 (s) 2 AlBr3 (aq) + 3 H₂(g) AH-1061 kJ HBr(aq) AH° -81.15 kJ 2 HBr(g) AH° -72.80 kJ AlBr3(aq) AH-368 kJ = =