A square loop of wire with side 0.60 m carries a current of 9.0 A as shown

Question:

A square loop of wire with side 0.60 m carries a current of 9.0 A as shown in the side-view diagram. When there is no applied magnetic field, the plane of the loop is horizontal and the nonconducting, nonmagnetic spring (k = 550 N/m) is unstretched. A horizontal magnetic field of magnitude 1.3 T is now applied. At what angle θ is the wire loop's new equilibrium position? Assume the spring remains vertical because θ is small.

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Question Posted: