Consider the two-dimensional plane stress field of the form r = r (r, ),

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Consider the two-dimensional plane stress field of the form σr = σr(r, θ), σθ = τ rθ = 0. This is commonly referred to as a radial stress distribution. For this case, first show that the equilibrium equations reduce to:

r or + 1 a r r (ra,) = 0

Next integrate this result to get σr = f(θ)/r where f(θ) is an arbitrary function of θ. Finally using compatibility relation (7.6.6), show that the final form for the non-zero stress is given by

Equation 7.6 .6

D(or +00) = 1 1-v  (ar+a)= (1 + v) JF, Fr + + r r 1 aFe r 30 aFr Fr 1 Fe - + + r r r 30 ...plane strain

r (A sin + B cos r ;0)

Note that this matches with the Flamant solution given in Section 8.4 .7

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