Using the results of Exercise 4.5, show that = E/ [2(1 + v)] and =

Using the results of Exercise 4.5, show that μ = E/ [2(1 + v)] and λ = Ev/ [(1 + v) (1 – 2v)].

Data from exercise 4.5

Following the steps outlined in the text, invert the form of Hooke’s law given by (4.2.7) and develop form (4.2.10). Explicitly show that E = μ(3λ + 2μ)/ (λ + μ) and v = λ/ [2(λ + μ)].

Equation 4.2.7

Equation 4.2.10

Transcribed Image Text:

dij ;; = ; + 2;; 2Meij