Using I DSS = 9 mA and V P = -3 V for the characteristics of Fig.
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Using IDSS = 9 mA and VP = -3 V for the characteristics of Fig. 6.22 , calculate I D at V GS = 1V using Shockley’s equation and compare to the level in Fig. 6.22.
Fig. 6.22
Transcribed Image Text:
Vas =0 V 2 9 mA Vertical Sens. 1 mA per div. Vas =-0.5 V Нorizontal Sens. per div. Vas =-1 V ass = 45 mA (Vas = -0.9 V) 500 mV per slep. -Vas =-1.5 V 2 m per div. ImA div Vas =-2 V V-3 V div
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Using IDSS 9 mA and VP 3 V for the characteristics of Fig 622 calculate I D at V G...View the full answer
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Related Book For
Electronic Devices And Circuit Theory
ISBN: 9781292025636
11th Edition
Authors: Robert Boylestad, Louis Nashelsky
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