The ethyl mercaptan concentration in a mixture was determined by shaking a 1 795 g sample with 50 00 mL of 0 01204 M I 2 in a tightly stoppered flask The excess I 2 was back titrated with 15 21 mL of 0 01437 M Na 2 S 2 O 3 Calculate the percentage of C 2 H 5 SH (62 13 g mol) 2CH5SH 1 CH5SSCH, 21 2H...

Solution The percemt of C2H5SH in the mixture can be calcul ...

The ethyl mercaptan concentration in a mixture was determined by shaking a 1.795-g sample with 50.00 mL

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The ethyl mercaptan concentration in a mixture was determined by shaking a 1.795-g sample with 50.00 mL of 0.01204 M I₂ in a tightly stoppered flask:

The excess I₂ was back-titrated with 15.21 mL of 0.01437 M Na₂S₂O₃. Calculate the percentage of C₂H₅SH (62.13 g/mol).

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Fundamentals Of Analytical Chemistry

ISBN: 9780357450390

10th Edition

Authors: Douglas A. Skoog, Donald M. West, F. James Holler, Stanley R. Crouch

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Question Posted: Jun 03, 2022 12:18 AM

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The ethyl mercaptan concentration in a mixture was determined by shaking a 1.795-g sample with 50.00 mL

Question:

2C₂H5SH + 1₂ →→C₂H5SSC₂H, +21¯ + 2H+

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Solution The percemt of C2H5SH in the mixture can be calcul...View the full answer

Fundamentals Of Analytical Chemistry

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