Question: A point charge Q is nailed down on a table. Around it, at radius R, is a frictionless circular track on which a dipole p
A point charge Q is “nailed down” on a table. Around it, at radius R, is a frictionless circular track on which a dipole p rides, constrained always to point tangent to the circle. Use Eq. 4.5 to show that the electric force on the dipole is![]()
Notice that this force is always in the “forward” direction (you can easily confirm this by drawing a diagram showing the forces on the two ends of the dipole). Why isn’t this a perpetual motion machine?
F - 0 P 470 R3
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