26. The width of a slot of a duralumin forging is (in inches) normally distributed with ...

Question:

26. The width of a slot of a duralumin forging is (in inches) normally distributed with

μ = .9000 and σ = .0030. The specification limits were given as .9000±.0050.

What percentage of forgings will be defective? What is the maximum allowable value of σ that will permit no more than 1 in 100 defectives when the widths are normally distributed with μ = .9000 and σ = .0030?

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Question Posted: