Let (lambda=lambda^{1}) be Lebesgue measure on ((mathbb{R}, mathscr{B}(mathbb{R}))). Show that (N in mathscr{B}(mathbb{R})) is a null set
Question:
Let \(\lambda=\lambda^{1}\) be Lebesgue measure on \((\mathbb{R}, \mathscr{B}(\mathbb{R}))\). Show that \(N \in \mathscr{B}(\mathbb{R})\) is a null set if, and only if, for every \(\epsilon>0\) there is an open set \(U_{\epsilon} \supset N\) such that \(\lambda\left(U_{\epsilon}ight)
[ sufficiency is trivial, for necessity use \(\lambda^{*}\) constructed in Theorem 6.1 from \(\left.\lambdaight|_{\mathscr{O}}\) and observe that \(\left.\lambdaight|_{\mathscr{B}\left(\mathbb{R}^{n}ight)}=\left.\lambda^{*}ight|_{\mathscr{B}\left(\mathbb{R}^{n}ight)}\). This gives the required open cover.]
Data from theorem 6.1
Fantastic news! We've Found the answer you've been seeking!
Step by Step Answer:
Related Book For
Question Posted: