An air gap capacitor with parallel plate area A discharges by the electrical breakdown of the air between its parallel plates (separation d) when the voltage between its plates exceeds V 0 Lay a slab with dielectric constant and thickness t d on the surface of the lower plate and maintain a potential difference V between the plates (a) Find the capacitance of this structure with the dielectric slab present (b) Show that the value of V where electric breakdown occurs in the air portion of the capacitor gap is V Vo 1 (1 1) V' d K

Question: An air-gap capacitor with parallel-plate area A discharges by the electrical breakdown of the air between its parallel plates (separation d) when the voltage between

An air-gap capacitor with parallel-plate area A discharges by the electrical breakdown of the air between its parallel plates (separation d) when the voltage between its plates exceeds V₀. Lay a slab with dielectric constant κ and thickness t

(a) Find the capacitance of this structure with the dielectric slab present.
(b) Show that the value of V where electric breakdown occurs in the air portion of the capacitor gap is V = Vo [1 -/- (1 - 1)]. V' d K

V = Vo [1 -/- (1 - 1)]. V' d K

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