A 72-kg woman is walking at (1.5 mathrm{~m} / mathrm{s}). An (8-mathrm{kg}) dog is running at six
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A 72-kg woman is walking at \(1.5 \mathrm{~m} / \mathrm{s}\). An \(8-\mathrm{kg}\) dog is running at six times that speed in the same direction. At what speed and in what direction relative to the woman would you have to be jogging in order for the dog to have the same momentum as the woman in your reference frame?
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Lets denote the velocity of the woman as vtextwoman and the velocity of the dog as vtextdog Given Ma...View the full answer
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