A ball launched directly upward from the ground at an initial speed of (24.5 mathrm{~m} / mathrm{s})
Question:
A ball launched directly upward from the ground at an initial speed of \(24.5 \mathrm{~m} / \mathrm{s}\) hits the ground \(5.0 \mathrm{~s}\) later. What are
(a) the ball's upward position 1. 0, 2. 0, 3. 0, and \(4.0 \mathrm{~s}\) after launch; \((b)\) its upward velocity \(1.0,2.0,3.0\) and \(4.0 \mathrm{~s}\) after launch;
(c) its average velocity while it is in the air; and \((d)\) its average speed for the entire trip?
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Step by Step Answer:
a To find the balls upward position at 10 20 30 and 40 texts after launch we can use the equations of motion for constant acceleration The ball is lau...View the full answer
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