Calculate the standard enthalpy of formation of FeS 2 (s) at 600. °C from the following data
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You are also given that for the reaction 2FeS2(s) + 11/2O2(g) Fe2O2(s) + 4SO2(g).HoR = - 1655 kJ mol-1
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Substance S(rhombic) so, (g) FeS:(s) Fe(s) Fe,03(s) -824.2 AH, (kJ mol-) -296.81 3.02 7.48 2.72 CP,/R
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2FeS 2 s 112O 2 gFe 2 O 2 s 4SO 2 gH o R 1655 kJ mol 1 1655 kJ mo...View the full answer
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