Question: Iminodiacetic acid forms 2:1 complexes with many metal ions: A 25.0 mL solution containing 0.120 M iminodiacetic acid buffered to pH 7.00 was titrated with

Iminodiacetic acid forms 2:1 complexes with many metal ions:

CH,CO,H H,Ñ CH,CO,H H,X* [X?-1 ax? [H;X*]+ [H2X] + [HX¯] + [X ] Cu²+ + 2x?- = CuX K = B2 = 3.5 × 1016

A 25.0 mL solution containing 0.120 M iminodiacetic acid buffered to pH 7.00 was titrated with 25.0 mL of 0.050 0 M Cu²⁺.Given that α_x2 = 4.6 × 10^-3 at pH 7.00, calculate [Cu²⁺] in the resulting solution.

CH,CO,H H, CH,CO,H H,X* [X?-1 ax? [H;X*]+ [H2X] + [HX] + [X ] Cu+ + 2x?- = CuX K = B2 = 3.5 1016

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