[0/12 Points] DETAILS PREVIOUS ANSWERS UWAPRECALC1 7.P.016. MY NOTES Sven starts walking due south at 5 feet per second from a point 160 feet north of an Intersection. At the same time Rudyard starts walking due east at 4 feet per second from a point 170 feet west of the Intersection. (a) Write an expression for the distance d between Sven and Rudyard t seconds after they start walking. d = V (160 - 5t)2 + (170-4t) 2 X (b) When are Sven and Rudyard closest? (Round your answer to two decimal places.) t = X s What Is the minimum distance between them? (Round your answer to two decimal places.) Additional Materials Reading Viewing Saved Work Revert to Last Response Submit Answer Submit Assignment Save Assignment Progress