1. In the following process diagram, calculate the indicated variables N2 - CH14 V =? P = 850 mmHg Ti =? Q2 =? C=? C6H14 Q1 =? E PE 850 mmHg Sy = 8% Te = 80 C Adiabatic dryer = F P = 850 mmHg Sy = 55% Te = 60C P=Constan B =? 4% C6H14 96% Solid Tg =? A=22,000 lb/h 23% C6H14 77% solid TA=45C InP, = A. = B T+C' P, in kPa y T in K A=14.0568 B=2825.42 C=-42.7089 CPC.H. (liq) a= 3.14210x101 b=9.76058x10-1 C=-2.35368x103 d=3.09273x10-6 J Cp en mol K CPsolid = 0.487 kcal kg C