11 3 84 points eBook Exercise 9 54 Algo Consider the following hypotheses Ho p 0 45 HA p 0 45 Compute the p value based on the following sample information (You may find it useful to reference the appropriate table z table or t table ) (Round final answers to 4 decimal places ) Print a x 42 n 105 b x 139 n 331 References c p 0 35 n 69 d p 0 35 n 456 p value TABLE 1 Standard Normal Curve Areas Entries in this table provide cumulative probabilities, that is, the area under the curve to the left of z For example, P(Z 1 52) 0 0643 A normal distribution curve with a median at 0 with a shaded area till negative z P (Capital Z less than or equal to negative z) z 3 9 3 8 3 7 3 6 3 5 3 4 3 3 0 00 0 01 0 0000 0 0000 0 0001 0 0001 0 0001 0 0001 0 0002 0 0002 0 0001 0 0001 0 0002 0 0002 0 0002 0 0002 0 0003 0 0003 0 0003 0 0003 0 0005 0 0005 0 0001 0 0001 3 2 3 0 2 9 2 8 2 7 2 6 0 0031 2 5 2 4 2 3 2 2 2 1 2 0 1 9 1 8 1 7 1 6 1 5 1 4 1 3 1 2 1 1 1 0 0 9 0 8 0 7 0 6 0 5 0 02 0 03 0 04 0 05 0 06 0 07 0 0000 0 0000 0 0000 0 0000 0 0000 0 0000 0 0000 0 0000 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0001 0 0002 0 0002 0 0002 0 0002 0 0002 0 0002 0 0003 0 0003 0 0003 0 0003 0 0003 0 0002 0 0005 0 0004 0 0004 0 0004 0 0004 0 0004 0 0004 0 00 0 0007 0 0007 0 0006 0 0006 0 0006 0 0006 0 0006 0 0005 0 0005 0 0005 3 1 0 0010 0 0009 0 0009 0 0009 0 0008 0 0008 0 0008 0 0008 0 0007 0 0007 0 0013 0 0013 0 0013 0 0012 0 0012 0 0011 0 0011 0 0011 0 0010 0 0010 0 0019 0 0018 0 0018 0 0017 0 0016 0 0016 0 0015 0 0015 0 0014 0 0014 0 0026 0 0025 0 0024 0 0023 0 0023 0 0022 0 0021 0 0021 0 0020 0 0019 0 0035 0 0034 0 0033 0 0032 0 0030 0 0029 0 0047 0 0045 0 0044 0 0043 0 0041 0 0040 0 0039 0 0062 0 0060 0 0059 0 0057 0 0055 0 0054 0 0052 0 0082 0 0080 0 0078 0 0075 0 0073 0 0071 0 0069 0 0107 0 0104 0 0102 0 0099 0 0096 0 0094 0 0091 0 0139 0 0136 0 0132 0 0129 0 0125 0 0122 0 0119 0 0179 0 0174 0 0170 0 0166 0 0162 0 0158 0 0154 0 0150 0 0228 0 0222 0 0217 0 0212 0 0207 0 0202 0 0197 0 0192 0 0287 0 0281 0 0274 0 0268 0 0262 0 0256 0 0250 0 0244 0 0239 0 0233 0 0359 0 0351 0 0344 0 0336 0 0329 0 0322 0 0314 0 0307 0 0301 0 0294 0 0446 0 0436 0 0427 0 0418 0 0409 0 0401 0 0392 0 0384 0 0375 0 036 0 0548 0 0537 0 0526 0 0516 0 0505 0 0495 0 0485 0 0475 0 0465 0 0455 0 0668 0 0655 0 0643 0 0630 0 0618 0 0606 0 0594 0 0582 0 0571 0 0559 0 0808 0 0793 0 0778 0 0764 0 0749 0 0735 0 0721 0 0708 0 0694 0 0681 0 0968 0 0951 0 0934 0 0918 0 0901 0 0885 0 0869 0 0853 0 0838 0 0823 0 1151 0 1131 0 1112 0 1093 0 1075 0 1056 0 1038 0 1020 0 1003 0 0985 0 1357 0 1335 0 1314 0 1292 0 1271 0 1251 0 1230 0 1210 0 1190 0 1170 0 1587 0 1562 0 1539 0 1515 0 1492 0 1469 0 1446 0 1423 0 1401 0 1379 0 1841 0 1814 0 1788 0 1762 0 1736 0 1711 0 1685 0 1660 0 1635 0 1611 0 2033 0 2005 0 1977 0 1949 0 1922 0 1894 0 1867 0 2206 0 2177 0 2148 0 2514 0 2483 0 2451 0 2843 0 2810 0 2776 0 08 0 09 0 0028 0 0027 0 0026 0 0038 0 0037 0 0036 0 0051 0 0049 0 0048 0 0068 0 0066 0 0064 0 0089 0 0116 0 0087 0 0084 0 0113 0 0110 0 0146 0 0143 0 0188 0 0183 0 4 0 3 0 2119 0 2090 0 2061 0 2420 0 2389 0 2358 0 2327 0 2296 0 2743 0 2709 0 2676 0 2643 0 2611 0 2578 0 3085 0 3050 0 3015 0 2981 0 2946 0 2912 0 2877 0 3446 0 3409 0 3372 0 3336 0 3300 0 3264 0 3228 0 3192 0 3156 0 3121 0 3821 0 3783 0 3745 0 3707 0 3669 0 3632 0 3594 0 3557 0 2 0 4207 0 4168 0 4129 0 4090 0 4052 0 4013 0 3974 0 3936 0 3897 0 3859 0 1 0 4602 0 4562 0 4522 0 4483 0 4443 0 4404 0 4364 0 4325 0 4286 0 4247 0 0 0 5000 0 4960 0 4920 0 4880 0 4840 0 4801 0 4761 0 4721 0 4681 0 4641 0 2266 0 2236 0 2546 0 3520 0 3483 Source Probabilities calculated with Excel TABLE 1 (Continued) Entries in this table provide cumulative probabilities, that is, the area under the curve to the left of z For example, P(Z 1 52) 0 9357 A normal distribution curve with a median at 0 with a shaded area till z P (Capital Z less than or equal to z) z 0 01 0 02 0 03 0 04 0 0 0 5040 0 5080 0 5120 0 5160 0 1 0 2 0 3 0 4 0 5 0 6 0 7 0 8 0 9 1 0 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 2 0 0 9772 0 9778 0 9783 0 9788 0 9793 0 9798 0 9803 2 1 2 2 2 3 2 4 2 5 2 6 2 7 2 8 2 9 0 9931 0 9948 0 9953 0 9955 0 9956 0 9957 0 9959 0 9960 0 9961 0 9965 0 9966 0 9967 0 9968 0 9969 0 9970 0 9971 0 9974 0 9975 0 9976 0 9977 0 9977 0 9978 0 9979 0 9981 0 9982 0 9982 0 9983 0 9984 3 0 0 9987 0 9987 0 9987 0 9988 0 9988 3 1 3 2 3 3 3 4 0 9990 0 9991 0 9991 0 9991 0 9992 0 9993 0 9993 0 9994 0 9994 0 9994 0 9995 0 9995 0 9995 0 9996 0 9996 0 9997 0 9997 0 9997 0 9997 0 9997 3 5 3 6 3 7 3 8 3 9 0 9932 0 9934 0 9936 0 9949 0 9951 0 9952 0 9962 0 9963 0 9964 0 9972 0 9973 0 9974 0 9979 0 9980 0 9981 0 9984 0 9985 0 9985 0 9986 0 9986 0 9989 0 9989 0 9989 0 9990 0 9990 0 9992 0 9992 0 9992 0 9993 0 9993 0 9994 0 9994 0 9995 0 9995 0 9995 0 9996 0 9996 0 9996 0 9996 0 9997 0 9997 0 9997 0 9997 0 9997 0 9998 0 9998 0 9998 0 9998 0 9998 0 9998 0 9998 0 9998 0 9998 0 9998 0 9998 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9998 0 9998 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 0 9999 1 0000 1 0000 1 0000 1 0000 1 0000 1 0000 1 0000 1 0000 1 0000 1 0000 Source Probabilities calculated with Excel 0 9943 0 9945 0 9946 0 00 0 08 0 09 0 5000 0 5199 0 5239 0 5279 0 5319 0 5359 0 5398 0 5438 0 5478 0 5517 0 5557 0 5596 0 5636 0 5675 0 5714 0 5753 0 5793 0 5832 0 5871 0 5910 0 5948 0 5987 0 6026 0 6064 0 6103 0 6141 0 6179 0 6217 0 6255 0 6293 0 6331 0 6368 0 6406 0 6443 0 6480 0 6517 0 6554 0 6591 0 6628 0 6664 0 6700 0 6736 0 6772 0 6808 0 6844 0 6879 0 6915 0 6950 0 6985 0 7019 0 7054 0 7088 0 7157 0 7190 0 722 0 7257 0 7291 0 7324 0 7357 0 7389 0 7422 0 7454 0 7486 0 7517 0 7549 0 7580 0 7611 0 7642 0 7673 0 7704 0 7734 0 7764 0 7794 0 7823 0 7852 0 7881 0 7910 0 7939 0 7967 0 7995 0 8023 0 8051 0 8078 0 8106 0 8133 0 8159 0 8186 0 8212 0 8238 0 8264 0 8289 0 8315 0 8340 0 8365 0 8389 0 8413 0 8438 0 8461 0 8485 0 8508 0 8531 0 8554 0 8577 0 8599 0 8621 0 8643 0 8665 0 8686 0 8708 0 8729 0 8749 0 8770 0 8790 0 8810 0 8830 0 8849 0 8869 0 8888 0 8907 0 8925 0 8944 0 8962 0 8980 0 8997 0 9015 0 9032 0 9049 0 9066 0 9082 0 9099 0 9115 0 9131 0 9147 0 9162 0 9177 0 9192 0 9207 0 9222 0 9236 0 9251 0 9265 0 9279 0 9292 0 9306 0 9319 0 9332 0 9345 0 9357 0 9370 0 9382 0 9394 0 9406 0 9418 0 9429 0 9441 0 9452 0 9463 0 9474 0 9484 0 9495 0 9505 0 9515 0 9525 0 9535 0 9545 0 9554 0 9564 0 9573 0 9582 0 9591 0 9599 0 9608 0 9616 0 9625 0 9633 0 9641 0 9649 0 9656 0 9664 0 9671 0 9678 0 9686 0 9693 0 9699 0 9706 0 9713 0 9719 0 9726 0 9732 0 9738 0 9744 0 9750 0 9756 0 9761 0 9767 0 9808 0 9812 0 9817 0 9821 0 9826 0 9830 0 9834 0 9838 0 9842 0 9846 0 9850 0 9854 0 985 0 9861 0 9864 0 9868 0 9871 0 9875 0 9878 0 9881 0 9884 0 9887 0 9890 0 9893 0 9896 0 9898 0 9901 0 9904 0 9906 0 9918 0 9920 0 9922 0 9925 0 9927 0 9929 0 9938 0 9940 0 9941 0 05 0 06 0 07 0 7123 0 9909 0 9911 0 9913 0 9916 TABLE 2 Student's Distribution Entries in this table provide the values of ta,df that correspond to a given upper tail area o and a specified number of degrees of freedom df For example, for a 0 05 and df 10, P(T10 1 812) 0 05 A normal distribution curve with the center at 0 with a shaded upper tail area right of t sub (alpha, d f) till t sub d f a df 1 0 200 1 376 0 100 3 078 2 1 061 1 886 0 050 0 025 6 314 12 706 2 920 4 303 0 010 31 821 0 005 63 657 6 965 9 925 3 0 978 1 638 2 353 3 182 4 541 5 841 4 0 941 1 533 2 132 2 776 3 747 4 604 5 0 920 1 476 2 015 2 571 3 365 4 032 6 0 906 1 440 1 943 2 447 3 143 3 707 7 0 896 1 415 1 895 2 365 2 998 3 499 8 0 889 1 397 1 860 2 306 2 896 3 355 9 0 883 1 383 1 833 2 262 2 821 3 250 10 0 879 1 372 1 812 2 228 2 764 3 169 11 0 876 1 363 1 796 2 201 2 718 3 106 12 0 873 1 356 1 782 2 179 2 681 3 055 13 0 870 1 350 1 771 2 160 2 650 3 012 14 0 868 1 345 1 761 2 145 2 624 2 977 15 0 866 1 341 1 753 2 131 2 602 2 947 16 0 865 1 337 1 746 2 120 2 583 2 921 17 0 863 1 333 1 740 2 110 2 567 2 898 18 0 862 1 330 1 734 2 101 2 552 2 878 19 0 861 1 328 1 729 2 093 2 539 2 861 20 0 860 1 325 1 725 2 086 2 528 2 845 21 0 859 1 323 1 721 2 080 518 2 831 22 0 858 1 321 1 717 2 074 2 508 2 819 23 0 858 1 319 1 714 2 069 2 500 2 807 24 0 857 1 318 1 711 2 064 2 492 2 797 25 0 856 1 316 1 708 2 060 2 485 2 787 26 0 856 1 315 1 706 2 056 2 479 2 779 27 0 855 1 314 1 703 2 052 2 473 2 771 28 0 855 1 313 1 701 2 048 2 467 2 763 29 0 854 1 311 1 699 2 045 2 462 2 756 30 0 854 1 310 1 697 2 042 2 457 2 750 31 0 853 1 309 1 696 2 040 2 453 2 744 32 0 853 1 309 1 694 2 037 2 449 2 738 33 0 853 1 308 1 692 2 035 2 445 2 733 34 0 852 1 307 1 691 2 032 2 441 2 728 35 0 852 1 306 1 690 2 030 2 438 2 724 36 0 852 1 306 1 688 2 028 2 434 2 719 37 0 851 1 305 1 687 2 026 2 431 2 715 38 0 851 1 304 1 686 2 024 2 429 2 712 39 0 851 1 304 1 685 2 023 2 426 2 708 40 0 851 1 303 1 684 2 021 2 423 2 704 41 0 850 1 303 1 683 2 020 2 421 2 701 42 0 850 1 302 1 682 2 018 2 418 2 698 43 0 850 1 302 1 681 2 017 2 416 2 695 44 0 850 1 301 1 680 2 015 2 414 2 692 45 0 850 1 301 1 679 2 014 2 412 2 690 46 0 850 1 300 1 679 2 013 2 410 2 687 47 0 849 1 300 1 678 2 012 2 408 2 685 48 0 849 1 299 1 677 2 011 2 407 2 682 49 0 849 1 299 1 677 2 010 2 405 2 680 50 0 849 1 299 1 676 2 009 2 403 2 678 51 0 849 1 298 1 675 2 008 2 402 2 676 52 0 849 1 298 1 675 2 007 2 400 2 674 53 0 848 1 298 1 674 2 006 2 399 2 672 54 0 848 1 297 1 674 2 005 2 397 2 670 55 0 848 1 297 1 673 2 004 2 396 2 668 56 0 848 1 297 1 673 2 003 2 395 2 667 57 0 848 1 297 1 672 2 002 2 394 2 665 58 0 848 1 296 1 672 2 002 2 392 2 663 59 0 848 1 296 1 671 2 001 2 391 2 662 60 0 848 1 296 1 671 2 000 2 390 2 660 80 0 846 1 292 1 664 1 990 2 374 2 639 100 0 845 1 290 1 660 1 984 2 364 2 626 150 0 844 1 287 1 655 1 976 2 351 2 609 200 0 843 1 286 1 653 1 972 2 345 2 601 500 1000 0 842 1 283 1 648 1 965 2 334 2 586 0 842 1 282 1 646 1 962 2 330 2 581 0 842 1 282 1 645 1 960 2 326 2 576 Source t values calculated with Excel

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11 3.84 points eBook Exercise 9-54 Algo Consider the following hypotheses: Ho: p 0.45 HA: p <0.45 Compute the p-value based on the following

11 3.84 points eBook Exercise 9-54 Algo Consider the following hypotheses: Ho: p 0.45 HA: p

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