Imagine that you are contracted by a local news provider to study consumer demographics in relation to three different types of news media: print (newspaper), Internet, and television. In prior market research, the company has classified each of its customers as receiving news content primarily from only one of these three sources, and as either urban or rural residents. In order to help design effective marketing strategies, you are asked to perform a test for equality of proportions to determine whether there is a significant difference in the proportion of consumers who live in urban versus rural areas for the three media types that are offered. The three population proportions that you are interested in are: P1 = proportion of urban consumers for the population of newspaper readers P2 = proportion of urban consumers for the population of Internet news readers P3 = proportion of urban consumers for the population of TV news consumers You conduct a hypothesis test with a .10 level of significance to determine whether the proportion of urban consumers is the same for all three news sources. The null and alternate hypotheses for your test are: Ho: You collect a random sample of 1,371 consumers of the company's news content. You find that 210 of the 335 newspaper consumers, 280 of the 434 Internet consumers, and 412 of the 602 TV consumers lived in urban areas. The data are summarized in the following table: Sample Results News Source Newspaper Internet TV Total Consumer Urban 210 280 412 902 Rural 125 154 190 469 Total 335 434 602 1,371 Expected Frequencies News Source Newspaper Internet TV Total 902 Consumer Urban Rural 469 Total 335 434 602 1,371 To conduct your hypothesis test, you use a chi-square distribution with test is y?- degrees of freedom. The chi-square test statistic for your Use the following table of selected values of the chi-square distribution to reach a condusion about your null hypothesis: Area in Upper Tail Degrees of Freedom .10 05 .025 .01 2.706 3,841 5.024 6.635 4.605 5.991 7.378 9.210 6.251 7.815 9.348 11.345 4. 7.779 9.488 11.143 13.277 9.236 11.070 12.833 15.086 6. 10.645 12.592 14.449 16.812 7. 12.017 14.067 16.013 18.475 13.362 15.507 17.535 20.090 9. 14.684 16.919 19.023 21.666 10 15.987 18.307 20.483 23.209 the null hypothesis. You that there is a difference in with a .10 level of significance, you consumer demographics among the three news media sources Imagine that you are contracted by a local news provider to study consumer demographics in relation to three different types of news media: print (newspaper), Internet, and television. In prior market research, the company has classified each of its customers as receiving news content primarily from only one of these three sources, and as either urban or rural residents. In order to help design effective marketing strategies, you are asked to perform a test for equality of proportions to determine whether there is a significant difference in the proportion of consumers who live in urban versus rural areas for the three media types that are offered. The three population proportions that you are interested in are: P1 = proportion of urban consumers for the population of newspaper readers P2 = proportion of urban consumers for the population of Internet news readers P3 = proportion of urban consumers for the population of TV news consumers You conduct a hypothesis test with a .10 level of significance to determine whether the proportion of urban consumers is the same for all three news sources. The null and alternate hypotheses for your test are: Ho: You collect a random sample of 1,371 consumers of the company's news content. You find that 210 of the 335 newspaper consumers, 280 of the 434 Internet consumers, and 412 of the 602 TV consumers lived in urban areas. The data are summarized in the following table: Sample Results News Source Newspaper Internet TV Total Consumer Urban 210 280 412 902 Rural 125 154 190 469 Total 335 434 602 1,371 Expected Frequencies News Source Newspaper Internet TV Total 902 Consumer Urban Rural 469 Total 335 434 602 1,371 To conduct your hypothesis test, you use a chi-square distribution with test is y?- degrees of freedom. The chi-square test statistic for your Use the following table of selected values of the chi-square distribution to reach a condusion about your null hypothesis: Area in Upper Tail Degrees of Freedom .10 05 .025 .01 2.706 3,841 5.024 6.635 4.605 5.991 7.378 9.210 6.251 7.815 9.348 11.345 4. 7.779 9.488 11.143 13.277 9.236 11.070 12.833 15.086 6. 10.645 12.592 14.449 16.812 7. 12.017 14.067 16.013 18.475 13.362 15.507 17.535 20.090 9. 14.684 16.919 19.023 21.666 10 15.987 18.307 20.483 23.209 the null hypothesis. You that there is a difference in with a .10 level of significance, you consumer demographics among the three news media sources Imagine that you are contracted by a local news provider to study consumer demographics in relation to three different types of news media: print (newspaper), Internet, and television. In prior market research, the company has classified each of its customers as receiving news content primarily from only one of these three sources, and as either urban or rural residents. In order to help design effective marketing strategies, you are asked to perform a test for equality of proportions to determine whether there is a significant difference in the proportion of consumers who live in urban versus rural areas for the three media types that are offered. The three population proportions that you are interested in are: P1 = proportion of urban consumers for the population of newspaper readers P2 = proportion of urban consumers for the population of Internet news readers P3 = proportion of urban consumers for the population of TV news consumers You conduct a hypothesis test with a .10 level of significance to determine whether the proportion of urban consumers is the same for all three news sources. The null and alternate hypotheses for your test are: Ho: You collect a random sample of 1,371 consumers of the company's news content. You find that 210 of the 335 newspaper consumers, 280 of the 434 Internet consumers, and 412 of the 602 TV consumers lived in urban areas. The data are summarized in the following table: Sample Results News Source Newspaper Internet TV Total Consumer Urban 210 280 412 902 Rural 125 154 190 469 Total 335 434 602 1,371 Expected Frequencies News Source Newspaper Internet TV Total 902 Consumer Urban Rural 469 Total 335 434 602 1,371 To conduct your hypothesis test, you use a chi-square distribution with test is y?- degrees of freedom. The chi-square test statistic for your Use the following table of selected values of the chi-square distribution to reach a condusion about your null hypothesis: Area in Upper Tail Degrees of Freedom .10 05 .025 .01 2.706 3,841 5.024 6.635 4.605 5.991 7.378 9.210 6.251 7.815 9.348 11.345 4. 7.779 9.488 11.143 13.277 9.236 11.070 12.833 15.086 6. 10.645 12.592 14.449 16.812 7. 12.017 14.067 16.013 18.475 13.362 15.507 17.535 20.090 9. 14.684 16.919 19.023 21.666 10 15.987 18.307 20.483 23.209 the null hypothesis. You that there is a difference in with a .10 level of significance, you consumer demographics among the three news media sources