2. A voltmeter connected to the thermocouple circuit below reads 14.575 mV. Compute the work. temperature T. Show your 14.575 mV e Cu 70F Cu Cu 70F 14.575 mV = e Cu,Cu,70 F 14.575 mV = e Cu,Cu,70F Cu, Fe, 45 F = 0 (it's not a thermocouple) Cu Convert to Celcius: e Law of intermediate metals: e 14.575 mV = e = = Cu, Fe, 45 F Fe,C,T 14.940 mV = D C, Fe, 45 F 14.575 mV = Fe, C.I Table is for Iron-Constantan, so e C,Fe,722C Fe,C,T Fe,C.T 45F water bath De (e Fe.C.T. Cu, Fe, 45 F Fe,C, 7.22 C D Fe,C,7.22 C e )(e C,Fe,7.22 C Fe,C,0 C 14.940 mV indicates T = 275 C,Cu, 45 F Fe,C,0 C' Fe,C,T De C,Fe,7.22 C Fe,C,0C Fe C,Cu,45 F ) 0.365 mV C C,Cu,45 F (e Fe,C, 7.22C Fe,C,T Fe,C,0C Interpolate the table for 7.22: 0.354 0.22(0.405 0.354) 0.365 14.575 mV = (e Fe.C.1 De Fe,C,7.22 C C,Fe, 45 F Fe,C,0 C De Fe,C,0C T Cu,Cu,70 F (add zero)