(3) Identify the domain and range of the relation, and determine whether the relation is a function {(-7, -12), (-3, -5), (1, 16), (8, 18)}(A) Domain: {-7, -3, 1, 8); Range: {-12, -5, 16, 18); Not a function(B) Domain: {-12, -5, 16, 18); Range: {-7, -3, 1, 8); Not a function(C) Domain: {-12, -5, 16, 18}; Range: {-7, -3, 1, 8); Function(D) Domain: {-7, -3, 1, 8); Range: {-12, -5, 16, 18); Function(4) Find the indicated function and write its domain in interval notation.p( x) = x² + 2x, q(x) = ?(1-x), (q/p)(x) = ?(A) (q/p)x = ?(1-x)/(x² + 2x); (-?, -2) U (-2, 0) U (0, ?)(B) (q/p)x = ?(1-x)/(x² + 2x); (-?, -2) U (-2, 0] U (0, 1](C) (q/p)x = ?(1-x)/(x² + 2x); (-?, -2) U (-2, 0) U (0, 1](D) (q/p)x = ?(1-x)/(x² + 2x); (-?, -2) U (-2, 0) U (0, ?)