4. The equation for projectile motion gives the height of a projectile y (m): g y= (tan)x- + Yo 2V cos200 where x (m) is the horizontal position, Vo (m) is the initial projectile speed, 60 (rad) is the initial angle, yo (m) is the initial height, and g = 9.81 (m/s) is the acceleration due to gravity. a) Create an x vector ranging from 0 to 80 m in steps of 5 m. b) Calculate the projectile's height for 00 = 15 to 75 in steps of 15. Assume Vo = 25 m/s and yo = 0 m. c) On one figure, plot y vs x for all five 60. Use a different marker and color for each curve. d) What is y when x = 30 m and 0 = 60? e) Negative heights make no sense in the context of this problem (well, they can...but let's say they don't), so set the lower y-limit on the plot to 0. f) Analyze your results. Are there any launch angles which produce the same end point? Which launch angle produces the farthest range? Are your results consistent with what you learned in basic physics? Remark: It is in your best interest to always read the MATLAB documentation for built-in functions, even if you think you know how to use them.