6.

Use these relations to solve the queries that follow:

employees(eid, name, salary,did,m_eid)

projects(pid,description)

works_on(eid, pid, hours)

departments(did, location)

Note that Pid is also the name of the project and m_eid is the manager id.

Solve in both SQL and Relational Algebra: List the name of the employee with the lowest salary not working on project with pid=3.

7.Use these relations to solve the queries that follow:

employees(eid, name, salary,did,m_eid)

projects(pid,description)

works_on(eid, pid, hours)

departments(did, location)

Note that Pid is also the name of the project and m_eid is the manager id.

Solve only in SQL: List the name of employees that work more hours on any project than the hours that employee eid=999 works on any project with description texas.

8.Use these relations to solve the queries that follow:

employees(eid, name, salary,did,m_eid)

projects(pid,description)

works_on(eid, pid, hours)

departments(did, location)

Note that Pid is also the name of the project and m_eid is the manager id.

Solve in both SQL and Relational Algebra: List the name of the project in which ALL employees from the admiistration department work on it at least 7 hours.