7. The data table compares men who viewed television violence with those who did not, in order to study the differences in physical abuse of the spouse. For the men in the table, test whether television violence and abusiveness are related, using a significance level of 0.05. Assume that the conditions for the chi-square test have been met. 1 Click the icon to view the technology output. Choose the correct null hypothesis (Ho) and alternative hypothesis (HA). A. Ho: For men, television violence and abusiveness have a p-value = 0.05. HA: For men, television violence and abusiveness have a p-value * 0.05. B. Ho: For men, television violence and abusiveness have equal proportions. HA: For men, television violence and abusiveness have non-equal proportions. C. Ho: For men, watching violent TV is not independent of abusiveness. HA: For men, watching violent TV is independent of abusiveness. OD. Ho: For men, watching violent TV is independent of abusiveness. HA: For men, watching violent TV is not independent of abusiveness. Determine the chi-square test statistic from the given output. (Type an integer or a decimal. Do not round.) TV Violence Physical Abuse High Low Yes 15 25 No 17 96 Screenshot 2023-04-02 at 4.19.01 PM 1: Chi-square test output Chi-Square Test: High TV Violence, Low TV Violence Expected counts are printed below observed counts. Chi-Square contributions are printed below expected counts. Low TV Total Determine the p-value from the given output. (Type an integer or a decimal. Do not round.) Yes Use the p-value found above and a significance level of 0.05 to form a conclusion. A. Fail to reject Ho and conclude that the two variables are related. B. Reject Ho and conclude that the two variables are not related. C. Reject Ho and conclude that the two variables are related. D. Fail to reject Ho and conclude that the two variables are not related. Total Screenshot 2023-0....15.54 PM High TV Violence Violence 15 25 40 8.37 31.63 5.261 1.391 No 17 96 113 23.63 89.37 1.862 0.492 32 Chi-Sq=9.006, DF = 1, P-value = 0.003 121 153