A box of 10kg mass is sitting on a floor with a coefficient of friction of 0.9. A force of 50N at 15 is applied to the box by pushing down one one of the corners of the box. What is the vertical acceleration of the object (in m/s^2)?

I did 10*9.8 + 50 sin 15 = 110.94

then -0.9(110.94) + 50cos15 = -51.55

-51.55/10 = -5.15 I calculate a final answer of -5.15, is that correct?