Question
a) Calculate the PH of a .225M solution of NaCN. The ka value of HCN = 6.2 * 10^-10 b) Calculate the PH of a
a) Calculate the PH of a .225M solution of NaCN. The ka value of HCN = 6.2 * 10^-10
b) Calculate the PH of a .045M solution of MnCl4. The ka value of Mn(H2o)7 = 4.14 * 10^-5. What is the [Cl]? Will the chloride ion concentration affect Ph? If so, how?
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Heat And Mass Transfer Fundamentals And Applications
Authors: Yunus Cengel, Afshin Ghajar
6th Edition
0073398195, 978-0073398198
