A stream of air at $100$KPa $(1$ bar$)$ pressure and $39\mathrm{.}1C$ is flowing on the top surface of a thin squared flat sheet of solid naphthalene of length

$0\mathrm{.}301m$ with a velocity of $22\frac{m}{s}.$ The heat transfer equation available for this situation is:

$=0\mathrm{.}664(Re{)}^{0\mathrm{.}5}(Pr{)}^{0\mathrm{.}333}$

The other data are:

Kinematic viscosity of air $=1\mathrm{.}55{10}^{-5}\frac{m^2}{s}$

Fraction of naphthalene at the air$-$solid naphthalene interface is $0\mathrm{.}7$

Consider a pure gas @ a point far from the interphase

The air does not diffuse in the solid sheet

Take $P$ and $T$ constants

$Re=2\mathrm{.}67{10}^5$

$Sc=2\mathrm{.}511$

$D_{AB}=0\mathrm{.}001\frac{m^2}{s}$

$R=8\mathrm{.}314\frac{\text{K}\text{P}\text{a}{m}^3}{\text{K}\text{m}\text{o}\text{l}K}$

Considering all the information bellow, the corresponding mass transfer coefficient over the flat plate in Kmo$\frac{l}{m^2}s$ is:

Write the answer in the exponential form. For example: $9\mathrm{.}791e-2$