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After applying L'Hospital's Rule once, we have lim 8(sec2(x)-1) So, we still have an indeterminate limit of type xox sec2(x) + tan(x) needed, and
After applying L'Hospital's Rule once, we have lim 8(sec2(x)-1) So, we still have an indeterminate limit of type xox sec2(x) + tan(x) needed, and we will do so here, applying the rule for a second time. To do so, we need to find additional derivatives. The derivative of 8(sec2(x) - 1) with respect to x is The derivative of x sec2(x) + tan(x) with respect to x is We recall that L'Hospital's Rule can be applied repeatedly as 0
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