An LPG is composed of $60\%$ by mole butane and $40\%$ by mole propane; A common householek LPG tank has a content volume $($the insides only$)$ of $24$ liters and is stored in room temperature. The pressure inside the tank is kept at $1\mathrm{.}7$MPa.

Determine the kilograms of "dry air" $($moisture not accounted; only $21\%$ v$/$v oxygen gas and the balance is nitrogen gas$)$ used for combustion when fully$-$consuming a tank of LPG$.$

Molecular weight of dry air is $29\frac{g}{m}ol.$

Assume ideal conditions.