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Assume gasoline to be 87 vol% iso-octane (2,2,4 tri-methyl pentane) and 13 vol% -heptane. At room temperature, the air above a pool of gasoline will

Assume gasoline to be 87 vol% iso-octane (2,2,4 tri-methyl pentane) and 13 vol% -heptane. At room temperature, the air above a pool of gasoline will become saturated

  1. Is the air-gasoline mixture within its flammable limits?
  2. Could there be any location where the mixture will be within its flammable limits? Explain.
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\begin{tabular}{|l|l|l|l|l|l|l|} \hline Component & Molar volume & xi & LFL & UFL & Pst @.298 K \\ \hline Lso-octane & 165.1ml/mol & 0.883 & 0.008 & 0.070 & 6530Pa \\ \hline u-heptane & 146.7ml/mol & 0.117 & 0.010 & 0.084 & 6050Pa \\ \hline \end{tabular}

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