Average Seet TIme : 6.5ms

Rotational Speed: 7200 rpm

Track Size: 800 sectors/track

Sector Size: 512 bytes/sector

Randomly Distributed File

Assuming a total access of 6.144MB (1MB = 10^6 bytes) and random accessedl that is the sectors are randomly distributed across all tracks.

Determine the Total Average Read or Write Time for the disk in terms of milliseconds.

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Sequentially Distributed File

Assuming the same total access of 6.144MB (1MB = 10^6 bytes) but sequentially accessed; that is the sectors are consecutively found within a track, continuing on to adjacent tracks.

Determine the Total Average Read or Write Time for the disk in terms of milliseconds.

I'll be honest I know how to do the first part (randomly distributed) but I thought I would just write it down anyways. I can't seem to figure out how to do the sequentially distributed part.

I think the answer is something like 194m/s but I'm not sure how to get there.

The formula is ..

T_total = T_s + (1/2r) + (b/rN)

= average seek time + rotational delay + transfer time

you just have to make sure to also convert correctly.

Thanks for any help!