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(b) Our result from part (a) shows that at 35 C, the slightly expanded tape reads a distance of 50.000 m when the true distance
(b) Our result from part (a) shows that at 35 C, the slightly expanded tape reads a distance of 50.000 m when the true distance is 50.009 m. We can rewrite the algebra of part (a) as L = Lo(1 + @ AT); at 35 C, any true distance will be greater than the reading by the factor 50.009/50.000 = 1 + a AT = 1 + 1.8 x 10 4. The true distance is therefore (1 + 1.8 X 10-4) (35.794 m) = 35.800 m
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