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C programming please give an explanation Assume a program had the code below and it was running on our ARM architecture. After main has returned,
C programming
please give an explanation
Assume a program had the code below and it was running on our ARM architecture. After main has returned, how would the values in the table have changed? Assume a little endian. void foo(uint8_t * ptr_a, uint32_t * ptr_b) { *ptr_a += 2: (*(uint8_t *)(ptr_b))++: ptr_b++: } int main() { uint32_t * ptr1 = (uint32_t *)0x300: uint8_t * ptr2 = (uint8_t *)0x302: (*(uint8_t*)(ptr1)) > > =1: ptr2++: *ptr1 += 512: foo(((uint8_t*)(0x305)), ptr1): ptr1++: *ptr1 -= 4: ptr2 += 2: (*ptr2)++: --*ptr1: return 0: } Assume a program had the code below and it was running on our ARM architecture. After main has returned, how would the values in the table have changed? Assume a little endian. void foo(uint8_t * ptr_a, uint32_t * ptr_b) { *ptr_a += 2: (*(uint8_t *)(ptr_b))++: ptr_b++: } int main() { uint32_t * ptr1 = (uint32_t *)0x300: uint8_t * ptr2 = (uint8_t *)0x302: (*(uint8_t*)(ptr1)) > > =1: ptr2++: *ptr1 += 512: foo(((uint8_t*)(0x305)), ptr1): ptr1++: *ptr1 -= 4: ptr2 += 2: (*ptr2)++: --*ptr1: return 0: }Step by Step Solution
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