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Can you please explain part C. I can't get it correct and zero is not the answer. 5. [0.66/1 Points] DETAILS PREVIOUS ANSWERS OSUNIPHYS1 23.4.WA.036.DEFECTIVE

Can you please explain part C. I can't get it correct and zero is not the answer.

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5. [0.66/1 Points] DETAILS PREVIOUS ANSWERS OSUNIPHYS1 23.4.WA.036.DEFECTIVE MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A spherical hollow conductor with an inner and outer radius of 0.152 m and 0.267 m respectively has a point charge of +61.0 nC at its center. Where applicable, express your answer using the i unit vector notation. Take the unit vector f to be directed radially outward from the center of the conductor. (a) What is the electric field at dj = 0.199 m from the center of the conductor? N /C (b) What is the surface charge density (magnitude and sign) on the inner surface of the conductor? -210.10 nc / m 2 (c) The surface charge density on the outer surface of the conductor has the same magnitude as that on the inner surface, but is of the opposite sign. What is the electric field vector at d2 = 0.154 m from the center of the conductor? E= X What is the total charge on the outer surface of the conductor? What is the net charge enclosed inside a spherical surface of radius dy? What is the direction of the electric field at this radius? N/C Submit Answer 6. [-/1 Points] DETAILS OSUNIPHYS1 23.4.WA.039.TUTORIAL. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A solid spherical non-conductor of radius 14.5 cm has a uniform charge density of p = 2.10 HC/m3. (a) Find the magnitude of the electric field at a distance of 9.70 cm from the center of the sphere. 0 N/C (b) Find the magnitude of the electric field at a distance of 23.0 cm from the center of the sphere. N/C (c) Now consider a solid spherical conductor of same radius with the same total charge as the non-conducting sphere in part (a). Find the electric field at the two distances indicated in parts (a) and (b). 78.F O 2:54 AM Partly cloudy W 5/7/2022 3

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