Question: Case Study: Simplified Educational ISA Design A team of computer science educators is designing a simplified Instruction Set Architecture ( ISA ) for use in
Case Study: Simplified Educational ISA Design
A team of computer science educators is designing a simplified Instruction Set Architecture ISA for use in introductory computer architecture courses. The goal is to help students understand the basics of ISA design, including the tradeoffs between instruction complexity, memory addressing, and the limitations imposed by a fixed instruction width. The ISA, named EduISA, is characterized by the following design choices:
Fixed Instruction Width: All instructions are bits long, aiming to simplify the decoding process and instruction execution.
Register File: EduISA uses a minimalistic approach with generalpurpose registers R to R encoded with bits.
Instruction Set: EduISA includes a small set of instructions:
LOADI: Load an immediate value into a register. Opcode:
ADD: Add two register values and store the result in a third register. Opcode:
SUB: Subtract one register value from another and store the result in a third register. Opcode:
STORE: Store a register value into a memory location using direct addressing. Opcode: ; the instruction uses the next bits to specify the memory address, making it a bit instruction for this case only.
Memory Addressing: EduISA supports direct addressing for the STORE instruction, allowing students to learn about memory operations. Due to the educational focus, a simplified memory model is used with addresses directly encoded in instructions when needed.
EduISA is intended to provide a handson learning experience, allowing students to write and execute simple programs that perform arithmetic operations and interact with memory.
Question points
Why does the STORE instruction in EduISA use a bit format?
Question options:
It is a design error and not intentional.
To provide extra space for encoding more complex operations.
To enable direct addressing of memory locations.
To allow for a larger range of immediate values.
Question points
What is the primary goal of the EduISA design?
Question options:
To facilitate learning about ISA design and operation.
To enable direct memory access for all instructions.
To support a wide range of complex instructions.
To maximize the performance of arithmetic operations.
Question points
EduISA's decision to limit registers to a bit encoding scheme impacts the processor's:
Question options:
Flexibility in register allocation and usage for optimizing program execution.
Ability to perform complex arithmetic operations directly in hardware.
Capacity for parallel processing and multithreading.
Overall power consumption and chip complexity.
Question points
What design tradeoff does the fixed bit instruction width in EduISA exemplify?
Question options:
A balance between decoding speed and the versatility of arithmetic operations.
A compromise between the number of available registers and the instruction set complexity.
A tradeoff between instruction simplicity and the ability to directly address a wide memory range.
A tradeoff between the instruction execution speed and memory access latency.
Question points
SetAssociative Mapping Exercises
Scenario: way setassociative cache, bit address, sets, word block size.
Question: How many bits are used for the tag, set, and word IDs?
Question options:
Word ID:
Set ID:
Tag ID:
Optional reasoning:
Question points
You are writing a loop that should execute a fixed number of times, determined by the value To set up the loop counter with this value, which addressing mode would you likely use?
Question options:
Indirect Addressing Mode
Immediate Addressing Mode
Direct Addressing Mode
Question points
Advanced Assembly Programming with Bitwise and Conditional Instructions
Objective: Dive deeper into assembly language programming by tackling scenarios that necessitate the use of bitwise operations and conditional branching, enriching understanding of practical instruction set applications.
Extended Instruction Set:
AND Rx Ry Rz: Executes a bitwise AND between the values in Ry and Rz storing the outcome in Rx
OR Rx Ry Rz: Executes a bitwise OR between the values in Ry and Rz storing the outcome in Rx
BNE Label: Branches to a specific label if the preceding comparison did not result in equality.
CMP Rx Ry: Compares the values in Rx and Ry preparing the stage for conditional branching based on the comparison's outcome.
Memory Table for Context:
Address Value
Tasks:
a Develop pseudoinstructions to perform a bitwise AND operation on the values at memory locations and and a bitwise OR operation on the values at and Then, store the AND result in and the OR result in
b Construct pseudoinstructions to compare the values at memory locations and If is greater, store in ; otherwise, store in
No PDF attachment required
Question options:
a: To perform the required bitwise operations and store the results, the sequence of pseudoinstructions is:
b: For the conditional comparison and storage based on the values at and the necessary pseudoinstructions are:
Question points
In the context of condition codes, what is a primary use of the Carry C flag?
Question options:
To indicate that the processor is carrying out a new instruction
To show that the operation did not result in any data being carried
To trigger an interrupt when an operation completes
To signal that an arithmetic operation resulted in a carry out or borrow into the most significant bit
Question points
Which data transfer method allows the CPU to continue with other tasks after initiating a transfer, only being interrupted upon completion?
Question options:
Interruptdriven IO
Programmed IO
Synchronous Data Transfer
Direct Memory Access DMA
Question points
Which of the following best describes the purpose of the Overflow V flag in a processor's status register?
Question options:
To signal that an arithmetic operation has produced a result too large to be represented in the allotted number of bits
To indicate whether the processor is currently handling an overflow of instructions
To flag when the processor has overflowed its instruction set
To determine if the processor's memory is overflowing
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