Consider the surface z=1-|x|-|y| which lies above and including the x-y plane. **Bounded** by z=1-|x| y=[-1,1] Find the limits of integration for the triple integral. (x in terms of y and z, y in terms of z). How can I represent y in terms of z if the limit of y is given already by y[-1,1]? That's what confusing me. I found the z limit to be 0