Convert the nfa defined by

$$

$($

$$

$0$

$,$

$$

$)$

$=$

$\{$

$$

$0$

$,$

$$

$1$

$\}$

$$

$($

$$

$1$

$,$

$$

$)$

$=$

$\{$

$$

$1$

$,$

$$

$2$

$\}$

$$

$($

$$

$2$

$,$

$$

$)$

$=$

$\{$

$$

$2$

$\}$

$$

$($

$$

$1$

$,$

$$

$)$

$=$

$\{$

$$

$1$

$,$

$$

$2$

$\}$

with initial state q$0$ and final state q$2$ into an equivalent dfa.