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Data for problems 7.9 (5 points each). In a recent survey, 20% of Kent State students prefer to eat lunch at the Market (MKT) located

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Data for problems 7.9 (5 points each). In a recent survey, 20% of Kent State students prefer to eat lunch at the Market (MKT) located on the 2nd floor Student Center, and 40% prefer the Eastway Fresh Food Company (EFF) located on the floor of the Eastway Center. The survey also found that 5% of the students equally prefer both MKT and EFF (Hint: Joint, Marginal and Conditional probability) MKT (MKT and EFF EFF 7. What percentage of those Kent State students who prefer EFF also prefer MKT? HINT Let MKT the event that a KSU student prefers KSC, and EFF = the event that a KSU student prefers Eastway P (MKT or EFF) - P(MKT) + P(EFF) - P(MKT and EFF) 7. Answer: 8. What percentage of Kent State students DO NOT prefer EFF? 8. Answer: 9. What percentage of Kent State students prefer EFF OR MKT OR both? 9. Answer: 10. (5 points ) It is estimated that 60% of the students on Kent Campus are commuter students Suppose you randomly selected a sample of 200 students on campus Sample: n = Population: Kent State students on campus. (X= 1)= a student on campus is a commuter student Parameters: p= the proportion of the commuter students p = Let: X the random variable representing the number of commuter students in the sample (COUNT) X - Binomial (n.p) a. (2 points) On average (mean), how many commuter students will be in your sample? 10a. Answer: b. (3 points) What is the standard deviation of the number of commuter students in your sample? 10b. Answer: 11. (15 points ) it is estimated that 60% of the students on Kent Campus are commuter students. Suppose you randomly selected a sample of 200 students on campus. What is the probability that more than 70% (0.70) of your sample are commuter students? HINT: Large sample proportion-use Normal approximation. Show the details of your calculations below. Population: Kent State students on campus. (X= 1)= a student on campus is a commuter student Parameters: pe the proportion of the commuter students p = Sample: n = Let: p = the proportion of commuter students in the sample If the sample size n is sufficiently large, then P - NORMAL (Hp. 0p) Op = a. (2 points) Verify that Normal approximation is appropriate. ; n(1-P) - Normal approximation is appropriate: YES or NO. (Circle one) Fall 2019, Data for problems 7.9 (5 points each). In a recent survey, 20% of Kent State students prefer to eat lunch at the Market (MKT) located on the 2nd floor Student Center, and 40% prefer the Eastway Fresh Food Company (EFF) located on the floor of the Eastway Center. The survey also found that 5% of the students equally prefer both MKT and EFF (Hint: Joint, Marginal and Conditional probability) MKT (MKT and EFF EFF 7. What percentage of those Kent State students who prefer EFF also prefer MKT? HINT Let MKT the event that a KSU student prefers KSC, and EFF = the event that a KSU student prefers Eastway P (MKT or EFF) - P(MKT) + P(EFF) - P(MKT and EFF) 7. Answer: 8. What percentage of Kent State students DO NOT prefer EFF? 8. Answer: 9. What percentage of Kent State students prefer EFF OR MKT OR both? 9. Answer: 10. (5 points ) It is estimated that 60% of the students on Kent Campus are commuter students Suppose you randomly selected a sample of 200 students on campus Sample: n = Population: Kent State students on campus. (X= 1)= a student on campus is a commuter student Parameters: p= the proportion of the commuter students p = Let: X the random variable representing the number of commuter students in the sample (COUNT) X - Binomial (n.p) a. (2 points) On average (mean), how many commuter students will be in your sample? 10a. Answer: b. (3 points) What is the standard deviation of the number of commuter students in your sample? 10b. Answer: 11. (15 points ) it is estimated that 60% of the students on Kent Campus are commuter students. Suppose you randomly selected a sample of 200 students on campus. What is the probability that more than 70% (0.70) of your sample are commuter students? HINT: Large sample proportion-use Normal approximation. Show the details of your calculations below. Population: Kent State students on campus. (X= 1)= a student on campus is a commuter student Parameters: pe the proportion of the commuter students p = Sample: n = Let: p = the proportion of commuter students in the sample If the sample size n is sufficiently large, then P - NORMAL (Hp. 0p) Op = a. (2 points) Verify that Normal approximation is appropriate. ; n(1-P) - Normal approximation is appropriate: YES or NO. (Circle one) Fall 2019

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