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delta =(PA)/(LE)+alpha LDelta T, , is this equation consistent? (circle one) Yes I No a. delta = displacement [in];L= length [mm];E=modulus of elasticity [Pa];A=area[m^(2)] ;

\\\\delta =(PA)/(LE)+\\\\alpha L\\\\Delta T,

, is this equation consistent? (circle one) Yes I No\ a.

\\\\delta =

displacement

[in];L=

length

[mm];E=modulus

of elasticity

[Pa];A=area[m^(2)]

;\

\\\\Delta T=

Temperature change

[\\\\deg R];P=

pressure

[mmHg];\\\\alpha =

coefficient of thermal expansion

(1)/(K)
image text in transcribed
3) =LEPA+LT, is this equation consistent? (circle one) Yes I No a. = displacement [in]; L= length [mm]; E= modulus of elasticity [Pa];A=area[m2]; T= Temperature change [R];P= pressure [mmHg];= coefficient of thermal expansion [1/K] 3) =LEPA+LT, is this equation consistent? (circle one) Yes I No a. = displacement [in]; L= length [mm]; E= modulus of elasticity [Pa];A=area[m2]; T= Temperature change [R];P= pressure [mmHg];= coefficient of thermal expansion [1/K]

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