Determine whether the given function is a solution to the given differential equation. d20 0 = e4t - 305t do at 2 - +50= - 43est dt The function 0 = e4t - 305t a solution to the differential equation d20 do dt 2 -0-+50= - 43e", because when e - 3e" is substituted for 0, dt is do substituted for d20 and dt is substituted for dt 2 the two sides of the differential equation equivalent on any intervals of t