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Use linear approximation, i.e. the tangent line, to approximate 2.883 as follows: Let f(ac) : $3. The equation of the tangent line to f(a:) at
Use linear approximation, i.e. the tangent line, to approximate 2.883 as follows: Let f(ac) : $3. The equation of the tangent line to f(a:) at :c : 3 can be written in the form y : mm + b where: m = and b: Using this, we nd our approximation for 2.883 is . (Round to two decimal places.) Use linear approximation, i.e. the tangent line, to approximate 0.504 as follows: Let f(x) = _ and find the equation of the tangent line to f(x) at a "nice" point near 0.504. Then use this to approximate 0.504 .A turkey is removed from the oven when its temperature reaches 185OF and is placed on a table in a room Where the temperature is 750F. After 10 minutes, the temperature of the turkey is 172OF, and after 20 minutes, it is 160F. Use a linear approximation to predict the temperature of the turkey after half an hour (use secant slopes as an approximation for the derivative). The gure below shows f(.13) and its local linearization at so : a, y : 4a: 3. (The local linearization is shown in blue.) What is the value of a? a, : What is the value of u)? f (a) : Use the linearization to approximate the value of f(2.2). rm) 2 Is the approximation an under or overestimate? (Enter under or over.) 1 33: Find the linear approximation at a: : 0 to . Write your answer in the form y : Am + B.
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