For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.

In a marketing survey, a random sample of996supermarket shoppers revealed that264always stock up on an item when they find that item at a real bargain price.

• (a)Letprepresent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain.

Find a point estimate forp. (Enter a number. Round your answer to four decimal places.)

• (b)Find a 95% confidence interval forp. (For each answer, enter a number. Round your answers to three decimal places.)

lower limit

upper limit

• Give a brief explanation of the meaning of the interval.

A. 5% of all confidence intervals would include the true proportion of shoppers who stock up on bargains.

B. 95% of all confidence intervals would include the true proportion of shoppers who stock up on bargains.

C. 5% of the confidence intervals created using this method would include the true proportion of shoppers who stock up on bargains.

D. 95% of the confidence intervals created using this method would include the true proportion of shoppers who stock up on bargains.

• (c)As a news writer, how would you report the survey results on the percentage of supermarket shoppers who stock up on items when they find the item is a real bargain?

A. Reportpalong with the margin of error.

B. Report the margin of error.

C. Report the confidence interval.

D. Reportp.

• What is the margin of error based on a 95% confidence interval? (Enter a number. Round your answer to three decimal places.)