Given that KNLM and LK>MN identify the two-column proof that proves mLMK>mMKN . Two triangles: KLM and KLN. Side LM is congruent to side KN. Angle KLM is congruent to angle KLN. 1.KNLM, LK>MN (Given)2.KMKM (Conv. of Hinge Thm.)3.mKML>mNKM (Reflex. Prop. of ) 1.KNLM, LK>MN (Given)2.KMKM (Reflex. Prop. of )3.mKML>mNKM (Conv. of Hinge Thm.) 1.KNLM, LK>MN (Given)2.KMKM (Hinge Thm.)3.mKML>mNKM (Reflex. Prop. of ) 1.KNLM, LK>MN (Given)2.KMKM (Reflex. Prop. of )3.mKML>mNKM (Hinge Thm.)