$[HI(g)]=1\mathrm{.}870mo\frac{l}{L}[H2(g)]=1\mathrm{.}065mo\frac{l}{L},[12(g)]=0\mathrm{.}065mo\frac{l}{L}.$ Calculate the value of $K$ for this equilibrium.

$0\mathrm{.}005$

$0\mathrm{.}044$

$1\mathrm{.}250$

$0\mathrm{.}020$