Here is the c$++$ code for the procedure. $($This is simply meant to help you understand the assignment!!$)\{$ cout $0$ endl;$\}$ cout &$$ "Please input a positive number" $$ endl;else $\{$ printFun$($n $-1)$; return;$\}$Requirements and Specifications

Your inputs n cannot be stored as a global variable at any point. This means you cannot store them at a data

section address, even when accepting them from scanf; they must be returned from scanf on the stack.

X$19-$X$27$ are global variables. You may not use X$19-$X$27$ in your recursive function. If you want, you may use X$19-$X$27$

in your main function. You can use any registers you want to in your main function.

A recursion procedure requires:

Allocate stack space

Save the return address and argument on the stack.

Recursively call procedure with BL

Unwind the stack by restoring the return address and arguments and deallocating stack memory

Hints and Warnings

You must put the argument and return address on the stack before any bl call, and restore the argument and the

return address after the bl call. This includes every printf call and every recursive call.

Here is my code so far, it works if you input any negative but the positive doesnt work or $0.$

$.$section $.$data

input$\_$number: $.$asciz "Please enter a number: $"$

input$\_$spec: $.$asciz $"\%$d$"$

print$\_$num: $.$asciz $"\%$d

$"$

error: $.$asciz "Please input a positive number

$"$

$.$section $.$bss

variable: $.$skip $4$

$.$section $.$text

$.$global main

main:

$//$ Print Input statement

ldr x$0,=$input$\_$number

bl printf

sub sp$,$ sp$,$ #$16$

$//$ Recieve input

ldr x$0,=$input$\_$spec

add x$1,$ sp$,$ #$8$

bl scanf

$//$ Check if input is negative

ldr w$0,[$sp$,$ #$8]$

cmp w$0,$ #$0$

blt input$\_$error

bl recurse

b exit

recurse:

sub sp$,$ sp$,$ #$16$

str w$1,[$sp$,$ #$8]$

str w$0,[$sp$,$ #$4]$

cmp w$0,$ #$0$

beq zero$\_$input

ldr x$0,=$print$\_$num

bl printf

sub w$0,$ w$0,$ #$1$

bl recurse

ldr x$0,=$print$\_$num

ldr w$0,[$sp$,$ #$4]$

bl printf

ldr w$1,[$sp$,$ #$8]$

add sp$,$ sp$,$ #$16$

ret

zero$\_$input:

ldr x$0,=$print$\_$num

bl printf

ldr w$1,[$sp$,$ #$8]$

add sp$,$ sp$,$ #$16$

ret

input$\_$error:

ldr x$0,=$error

bl printf

b exit

exit:

$//$ Exit syscall

mov x$0,0$

mov x$8,93$

svc $0$

ret