How do you compute

A nutritionist claims that the mean tuna consumption by a person is 3.7 pounds per year. Asample of 70 people shows that the mean tuna consumption by a person is 3.5 pounds per year. Assume the population standard deviation is 1.16 pounds. At =0.03, can you reject the claim? (a) Identify the null hypothesis and altemative hypothesis. OA. Ho: 1= 3.7 O B. Hy: 153.7 O C. Hy: 1#3.5 H_: 1#3.7 H_: 1 > 3.7 H_: p=3.5 OD. Hp: 14 > 3.5 OE. Hy: H > 3.7 OF. Hy: A$ 3.5 H_: p=3.5 H_: ps3.7 H_: p > 3.5 (b) Identify the standardized test statistic. z= (Round to two decimal places as needed.) (@) Find the P-value. (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O M. Reject Hp. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.7 pounds. O B. Reject Hy. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.7 pounds. O C. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.7 pounds. O D. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.7 pounds