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How much iron(III) sulfate (Fe 2 (SO 4 ) 3 ) can be formed from 125.0 mL of 0.250 M sulfuric acid (H 2 SO

How much iron(III) sulfate (Fe2(SO4)3) can be formed from 125.0 mL of 0.250 M sulfuric acid (H2SO4) and excess iron(III) nitrate (Fe(NO3)3), according to the following balanced equation?

2Fe(NO3)3(aq) + 3H2SO4(aq) ? Fe2(SO4)3(s) + 6HNO3(aq)

 

 

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