I just need help with understanding the grouping of bits. I know that the entire bit address should be $2^15$ with an offset of $10.$ What I don't understand is how the bits should be grouped so that we know what is VPN$1$ VPN$2$ and the offset. For example, if we had something $10$ VPN and $5$ offset I know just because to group the binary into five $(011111010011001)$ but what if the vpn and offset is different? How do I interpret that is my question. Thank you.

With simple linear $($array$-$based$)$ page tables, assume we have the following page table,

starting with the first entry and going to the last $($each row is a PTE$).$ Assuming this is the

entire page table, and the page size is $1$ KB $.($points $16\mathrm{.}7)$

$0$x$8000002$a

$0$x$00000000$

$0$x$00000000$

$0$x$00000000$

$0$x$8000003$e

$0$x$00000000$

$0$x$80000017$

$0$x$00000000$

$0$x$00000000$

$0$x$8000000$e

$0$x$00000000$

$0$x$00000000$

$0$x$8000001$f

$0$x$00000000$

$0$x$8000001$a

$0$x$80000001$

Assuming this is the entire page table, and that each page is $1$ K $,$ we can see that we have a

virtual address space of size $32$ KB $($process size$).$ Regardless weather the statement is true or

false.

Consider the following information. Now let's look at how to do a translation. The format of each

page table entry $($PTE$)$ above is as follows: A single valid $($the number $0$xx$8$ is valid and $0$xx$0$ is invalid$)$

bit followed by the PFN $($page frame number$)$; you might recall this from class how the ensemble the

real address: FPN concatenate with old offset.

Let's translate the following virtual address: $0$x$33$ef$.($points $16\mathrm{.}7)$