In the free-body diagram below you can see that a box with a mass of 9.8 Kg has three forces applied to it. If the first force (F1) is 27 N; the second force (F2) is 4 N; and the third force (F3) is 6 N, then what is the acceleration of the box? (Answer in only numbers to two decimal places. Remember that you need to find net force first and the vectors to the left and down are negative. Use the formula FNET = > F1 + F2 + F3 + ect. and the formula FNET = m . a)