In this virtual lab, calorimetry will be performed to determine the heat capacity, al,Cal, of a coffee cup calorimeter.

Imagine that, in lab, the mass of a piece of iron is recorded, Fe,mFe, as

Fe=51.46 gmFe=51.46 g

In the next step of the lab (as shown in the first image) the piece of metal is heated up.

Record the metal's highest temperature, Fe.TFe.

Fe=TFe=

CC

Next, the metal should be dropped into the coffee cup calorimeter. Please continue to the next image.

In another step of this lab, the mass of ethanol (ethanol)(methanol) in a coffee cup is recorded as

ethanol=63.94 gmethanol=63.94 g

The initial temperature of the ethanol, ethanol1,Tethanol1, is given to be 14.0 C.14.0 C.

In the next step of the lab (as shown in the second image) the hot piece of iron is placed into the cool ethanol.

Record the final temperature of the ethanol. Note this also serves as the final temperature of the metal.

ethanol2=Tethanol2=

CC

In the final step, using the specific heats (2.420 and 0.4498 J/(gC)J/(gC) for ethanol and iron, respectively) and the mass of ethanol and iron given, calculate the heat, taken up by the ethanol, ethanol,qethanol, and the heat given off by the metal, iron,qiron, and record them.

ethanol=qethanol=

J

iron=qiron=

J

Calculate the heat absorbed by the calorimeter.

cal=qcal=

J

With the given information please calculate the heat capacity, cal,Ccal, of the calorimeter.

cal=Ccal=

J/CJ/C

How many significant figures does the calorimeter heat capacity have?