Organizers of a fishing tournament believe that the lake holds a sizable population of largemouth bass. They assume that the weights of these fish have a model that is skewed to the right with a mean of 5.5 pounds and a standard deviation of 1.19 pounds. Use this information to answer parts a through e. a) Why does a skewed model make sense here? A. A skewed to the right model makes sense because it would be expected that there are many small fish and only a few large ones in the lake. Your answer is correct.B. A skewed to the right model makes sense because only the large fish are catchable. C. A skewed to the right model does not make sense. b) Explain why you cannot use a Normal model to determine the probability that a largemouth bass randomly selected ("caught") from the lake weighs over 5 pounds. Choose the correct answer below. A. The number of largemouth bass caught in the contest is not given so it is not possible to determine the probability. B. Since the distribution is not Normal and the exact distribution is not given, it is not possible to determine the probability. Your answer is correct.C. The standard deviation of the data is too large follow a Normal model. D. Since catching a fish is not perfectly random, the probability cannot be calculated. c) Each contestant catches 15 fish each day. Is it possible to determine the probability that someone's catch averages more than 5 pounds? If it is possible, determine the probability. A. The probability is nothing. (Round to three decimal places as needed.) B. Since the distribution is skewed to the right and the sample size of 15 is not large enough to use the Central Limit Theorem, it is not possible to determine the probability. Your answer is correct. d) The 12 contestants competing each caught the limit of 15 fish. What is the standard deviation of the mean weight of the 180 fish caught? SD(y)=nothing (Round to two decimal places as needed.)